The reaction of 3-methoxyphenylethylamine (I) with phenylethyl bromide (II) in refluxing triethylamine gives 3-methoxy-N-(phenylethyl)phenylethylamine (III), which is alkylated with 1-iodopropane by means of K2CO3 in refluxing acetone yielding 3-methoxy-N-propyl-N-(phenylethyl)phenylethylamine (IV). Finally, this compound is demethylated by treatment with refluxing aqueous 48% HBr and formation of the HCl salt with hydrochloric acid.