The reaction of ethanolimine (I) with m-methoxyphenylacetone (II) gives the corresponding Schiff base (III), which is reduced with H2 over Pd/C to the corresponding secondary amine (IV). Methylation of (IV) with HCHO-HCOOH yields 1-(m-methoxyphenyl)-2-(N-(2-hydroxyethyl)-N-methylaminoipropane (V), which is treated with SOCl2 to afford the 2-chloroethyl derivative (VI). Finally, this compound is condensed with benzhydrol (VII) by means of NaNH2 in refluxing benzene, and treated with HCl.