This compound can be obtained by four different ways: 1) By condensation of 5,6,7,8-tetrahydro-2-naphthol (I) with N-(6-methoxy-2-pyridyl)-N-methylthiocarbamoyl chloride (II) by means of K2CO3 in refluxing butanone. 2) By condensation of 2-naphthyloxythiocarbonyl chloride (III) with 6-methoxy-2-(methylamino)pyridine (IV) by means of K2CO3 in acetone. 3) The reaction of pyridine (IV) with CS2 and NaOH in THF gives N-(6-methoxy-2-pyridyl)-N-methyldithiocarbamic acid sodium salt (V), which is then condensed with 2-(2,4-dinitrophenoxy)-5,6,7,8-tetrahydronaphthalene (VI) in DMF. 4) The reaction of the dithiocarbamate (V) with 2,4-dinitrochlorobenzene (VII) in ethanol gives N-(6-methoxy-2-pyridyl)-N-methyldithiocarbamic acid 2,4-dinitrophenyl ester (VIII), which is then treated with naphthol (I) and sodium methoxide in DMF.